2500=25x^2

Solution for 2500=25x^2 equation:

2500=25x^2

We move all terms to the left:

2500-(25x^2)=0

a = -25; b = 0; c = +2500;
Δ = b2-4ac
Δ = 02-4·(-25)·2500
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-500}{2*-25}=\frac{-500}{-50}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+500}{2*-25}=\frac{500}{-50}
=-10
$